Integrand size = 21, antiderivative size = 168 \[ \int \frac {\sec ^2(c+d x)}{(a+a \cos (c+d x))^5} \, dx=-\frac {5 \text {arctanh}(\sin (c+d x))}{a^5 d}+\frac {496 \tan (c+d x)}{63 a^5 d}-\frac {\tan (c+d x)}{9 d (a+a \cos (c+d x))^5}-\frac {5 \tan (c+d x)}{21 a d (a+a \cos (c+d x))^4}-\frac {29 \tan (c+d x)}{63 a^2 d (a+a \cos (c+d x))^3}-\frac {67 \tan (c+d x)}{63 a^3 d (a+a \cos (c+d x))^2}-\frac {5 \tan (c+d x)}{d \left (a^5+a^5 \cos (c+d x)\right )} \]
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Time = 0.66 (sec) , antiderivative size = 168, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {2845, 3057, 2827, 3852, 8, 3855} \[ \int \frac {\sec ^2(c+d x)}{(a+a \cos (c+d x))^5} \, dx=-\frac {5 \text {arctanh}(\sin (c+d x))}{a^5 d}+\frac {496 \tan (c+d x)}{63 a^5 d}-\frac {5 \tan (c+d x)}{d \left (a^5 \cos (c+d x)+a^5\right )}-\frac {67 \tan (c+d x)}{63 a^3 d (a \cos (c+d x)+a)^2}-\frac {29 \tan (c+d x)}{63 a^2 d (a \cos (c+d x)+a)^3}-\frac {5 \tan (c+d x)}{21 a d (a \cos (c+d x)+a)^4}-\frac {\tan (c+d x)}{9 d (a \cos (c+d x)+a)^5} \]
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Rule 8
Rule 2827
Rule 2845
Rule 3057
Rule 3852
Rule 3855
Rubi steps \begin{align*} \text {integral}& = -\frac {\tan (c+d x)}{9 d (a+a \cos (c+d x))^5}+\frac {\int \frac {(10 a-5 a \cos (c+d x)) \sec ^2(c+d x)}{(a+a \cos (c+d x))^4} \, dx}{9 a^2} \\ & = -\frac {\tan (c+d x)}{9 d (a+a \cos (c+d x))^5}-\frac {5 \tan (c+d x)}{21 a d (a+a \cos (c+d x))^4}+\frac {\int \frac {\left (85 a^2-60 a^2 \cos (c+d x)\right ) \sec ^2(c+d x)}{(a+a \cos (c+d x))^3} \, dx}{63 a^4} \\ & = -\frac {\tan (c+d x)}{9 d (a+a \cos (c+d x))^5}-\frac {5 \tan (c+d x)}{21 a d (a+a \cos (c+d x))^4}-\frac {29 \tan (c+d x)}{63 a^2 d (a+a \cos (c+d x))^3}+\frac {\int \frac {\left (570 a^3-435 a^3 \cos (c+d x)\right ) \sec ^2(c+d x)}{(a+a \cos (c+d x))^2} \, dx}{315 a^6} \\ & = -\frac {\tan (c+d x)}{9 d (a+a \cos (c+d x))^5}-\frac {5 \tan (c+d x)}{21 a d (a+a \cos (c+d x))^4}-\frac {29 \tan (c+d x)}{63 a^2 d (a+a \cos (c+d x))^3}-\frac {67 \tan (c+d x)}{63 a^3 d (a+a \cos (c+d x))^2}+\frac {\int \frac {\left (2715 a^4-2010 a^4 \cos (c+d x)\right ) \sec ^2(c+d x)}{a+a \cos (c+d x)} \, dx}{945 a^8} \\ & = -\frac {\tan (c+d x)}{9 d (a+a \cos (c+d x))^5}-\frac {5 \tan (c+d x)}{21 a d (a+a \cos (c+d x))^4}-\frac {29 \tan (c+d x)}{63 a^2 d (a+a \cos (c+d x))^3}-\frac {67 \tan (c+d x)}{63 a^3 d (a+a \cos (c+d x))^2}-\frac {5 \tan (c+d x)}{d \left (a^5+a^5 \cos (c+d x)\right )}+\frac {\int \left (7440 a^5-4725 a^5 \cos (c+d x)\right ) \sec ^2(c+d x) \, dx}{945 a^{10}} \\ & = -\frac {\tan (c+d x)}{9 d (a+a \cos (c+d x))^5}-\frac {5 \tan (c+d x)}{21 a d (a+a \cos (c+d x))^4}-\frac {29 \tan (c+d x)}{63 a^2 d (a+a \cos (c+d x))^3}-\frac {67 \tan (c+d x)}{63 a^3 d (a+a \cos (c+d x))^2}-\frac {5 \tan (c+d x)}{d \left (a^5+a^5 \cos (c+d x)\right )}-\frac {5 \int \sec (c+d x) \, dx}{a^5}+\frac {496 \int \sec ^2(c+d x) \, dx}{63 a^5} \\ & = -\frac {5 \text {arctanh}(\sin (c+d x))}{a^5 d}-\frac {\tan (c+d x)}{9 d (a+a \cos (c+d x))^5}-\frac {5 \tan (c+d x)}{21 a d (a+a \cos (c+d x))^4}-\frac {29 \tan (c+d x)}{63 a^2 d (a+a \cos (c+d x))^3}-\frac {67 \tan (c+d x)}{63 a^3 d (a+a \cos (c+d x))^2}-\frac {5 \tan (c+d x)}{d \left (a^5+a^5 \cos (c+d x)\right )}-\frac {496 \text {Subst}(\int 1 \, dx,x,-\tan (c+d x))}{63 a^5 d} \\ & = -\frac {5 \text {arctanh}(\sin (c+d x))}{a^5 d}+\frac {496 \tan (c+d x)}{63 a^5 d}-\frac {\tan (c+d x)}{9 d (a+a \cos (c+d x))^5}-\frac {5 \tan (c+d x)}{21 a d (a+a \cos (c+d x))^4}-\frac {29 \tan (c+d x)}{63 a^2 d (a+a \cos (c+d x))^3}-\frac {67 \tan (c+d x)}{63 a^3 d (a+a \cos (c+d x))^2}-\frac {5 \tan (c+d x)}{d \left (a^5+a^5 \cos (c+d x)\right )} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(393\) vs. \(2(168)=336\).
Time = 5.52 (sec) , antiderivative size = 393, normalized size of antiderivative = 2.34 \[ \int \frac {\sec ^2(c+d x)}{(a+a \cos (c+d x))^5} \, dx=\frac {322560 \cos ^{10}\left (\frac {1}{2} (c+d x)\right ) \left (\log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )-\log \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )\right )+\cos \left (\frac {1}{2} (c+d x)\right ) \sec \left (\frac {c}{2}\right ) \sec (c) \sec (c+d x) \left (-33978 \sin \left (\frac {d x}{2}\right )+52002 \sin \left (\frac {3 d x}{2}\right )-56952 \sin \left (c-\frac {d x}{2}\right )+43722 \sin \left (c+\frac {d x}{2}\right )-47208 \sin \left (2 c+\frac {d x}{2}\right )-18144 \sin \left (c+\frac {3 d x}{2}\right )+41796 \sin \left (2 c+\frac {3 d x}{2}\right )-28350 \sin \left (3 c+\frac {3 d x}{2}\right )+34578 \sin \left (c+\frac {5 d x}{2}\right )-5691 \sin \left (2 c+\frac {5 d x}{2}\right )+28719 \sin \left (3 c+\frac {5 d x}{2}\right )-11550 \sin \left (4 c+\frac {5 d x}{2}\right )+15517 \sin \left (2 c+\frac {7 d x}{2}\right )-504 \sin \left (3 c+\frac {7 d x}{2}\right )+13186 \sin \left (4 c+\frac {7 d x}{2}\right )-2835 \sin \left (5 c+\frac {7 d x}{2}\right )+4149 \sin \left (3 c+\frac {9 d x}{2}\right )+252 \sin \left (4 c+\frac {9 d x}{2}\right )+3582 \sin \left (5 c+\frac {9 d x}{2}\right )-315 \sin \left (6 c+\frac {9 d x}{2}\right )+496 \sin \left (4 c+\frac {11 d x}{2}\right )+63 \sin \left (5 c+\frac {11 d x}{2}\right )+433 \sin \left (6 c+\frac {11 d x}{2}\right )\right )}{2016 a^5 d (1+\cos (c+d x))^5} \]
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Time = 1.17 (sec) , antiderivative size = 131, normalized size of antiderivative = 0.78
method | result | size |
derivativedivides | \(\frac {\frac {\left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{9}+\frac {8 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{7}+6 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+24 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+129 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-\frac {16}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1}+80 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )-\frac {16}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1}-80 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{16 d \,a^{5}}\) | \(131\) |
default | \(\frac {\frac {\left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{9}+\frac {8 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{7}+6 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+24 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+129 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-\frac {16}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1}+80 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )-\frac {16}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1}-80 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{16 d \,a^{5}}\) | \(131\) |
parallelrisch | \(\frac {40320 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) \cos \left (d x +c \right )-40320 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right ) \cos \left (d x +c \right )+31846 \left (\cos \left (d x +c \right )+\frac {10010 \cos \left (2 d x +2 c \right )}{15923}+\frac {4253 \cos \left (3 d x +3 c \right )}{15923}+\frac {2165 \cos \left (4 d x +4 c \right )}{31846}+\frac {124 \cos \left (5 d x +5 c \right )}{15923}+\frac {18359}{31846}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sec ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8064 a^{5} d \cos \left (d x +c \right )}\) | \(132\) |
norman | \(\frac {-\frac {161 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{16 d a}+\frac {105 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16 d a}+\frac {9 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d a}+\frac {17 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{56 d a}+\frac {65 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{1008 d a}+\frac {\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )}{144 d a}}{\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) a^{4}}+\frac {5 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{a^{5} d}-\frac {5 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{a^{5} d}\) | \(174\) |
risch | \(\frac {2 i \left (315 \,{\mathrm e}^{10 i \left (d x +c \right )}+2835 \,{\mathrm e}^{9 i \left (d x +c \right )}+11550 \,{\mathrm e}^{8 i \left (d x +c \right )}+28350 \,{\mathrm e}^{7 i \left (d x +c \right )}+47208 \,{\mathrm e}^{6 i \left (d x +c \right )}+56952 \,{\mathrm e}^{5 i \left (d x +c \right )}+52002 \,{\mathrm e}^{4 i \left (d x +c \right )}+34578 \,{\mathrm e}^{3 i \left (d x +c \right )}+15517 \,{\mathrm e}^{2 i \left (d x +c \right )}+4149 \,{\mathrm e}^{i \left (d x +c \right )}+496\right )}{63 d \,a^{5} \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )^{9} \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}+\frac {5 \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{a^{5} d}-\frac {5 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )}{a^{5} d}\) | \(191\) |
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Time = 0.29 (sec) , antiderivative size = 278, normalized size of antiderivative = 1.65 \[ \int \frac {\sec ^2(c+d x)}{(a+a \cos (c+d x))^5} \, dx=-\frac {315 \, {\left (\cos \left (d x + c\right )^{6} + 5 \, \cos \left (d x + c\right )^{5} + 10 \, \cos \left (d x + c\right )^{4} + 10 \, \cos \left (d x + c\right )^{3} + 5 \, \cos \left (d x + c\right )^{2} + \cos \left (d x + c\right )\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) - 315 \, {\left (\cos \left (d x + c\right )^{6} + 5 \, \cos \left (d x + c\right )^{5} + 10 \, \cos \left (d x + c\right )^{4} + 10 \, \cos \left (d x + c\right )^{3} + 5 \, \cos \left (d x + c\right )^{2} + \cos \left (d x + c\right )\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) - 2 \, {\left (496 \, \cos \left (d x + c\right )^{5} + 2165 \, \cos \left (d x + c\right )^{4} + 3633 \, \cos \left (d x + c\right )^{3} + 2840 \, \cos \left (d x + c\right )^{2} + 946 \, \cos \left (d x + c\right ) + 63\right )} \sin \left (d x + c\right )}{126 \, {\left (a^{5} d \cos \left (d x + c\right )^{6} + 5 \, a^{5} d \cos \left (d x + c\right )^{5} + 10 \, a^{5} d \cos \left (d x + c\right )^{4} + 10 \, a^{5} d \cos \left (d x + c\right )^{3} + 5 \, a^{5} d \cos \left (d x + c\right )^{2} + a^{5} d \cos \left (d x + c\right )\right )}} \]
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\[ \int \frac {\sec ^2(c+d x)}{(a+a \cos (c+d x))^5} \, dx=\frac {\int \frac {\sec ^{2}{\left (c + d x \right )}}{\cos ^{5}{\left (c + d x \right )} + 5 \cos ^{4}{\left (c + d x \right )} + 10 \cos ^{3}{\left (c + d x \right )} + 10 \cos ^{2}{\left (c + d x \right )} + 5 \cos {\left (c + d x \right )} + 1}\, dx}{a^{5}} \]
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Time = 0.30 (sec) , antiderivative size = 206, normalized size of antiderivative = 1.23 \[ \int \frac {\sec ^2(c+d x)}{(a+a \cos (c+d x))^5} \, dx=\frac {\frac {2016 \, \sin \left (d x + c\right )}{{\left (a^{5} - \frac {a^{5} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}\right )} {\left (\cos \left (d x + c\right ) + 1\right )}} + \frac {\frac {8127 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {1512 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {378 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} + \frac {72 \, \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}} + \frac {7 \, \sin \left (d x + c\right )^{9}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{9}}}{a^{5}} - \frac {5040 \, \log \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + 1\right )}{a^{5}} + \frac {5040 \, \log \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - 1\right )}{a^{5}}}{1008 \, d} \]
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Time = 0.44 (sec) , antiderivative size = 155, normalized size of antiderivative = 0.92 \[ \int \frac {\sec ^2(c+d x)}{(a+a \cos (c+d x))^5} \, dx=-\frac {\frac {5040 \, \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right )}{a^{5}} - \frac {5040 \, \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right )}{a^{5}} + \frac {2016 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )} a^{5}} - \frac {7 \, a^{40} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 72 \, a^{40} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 378 \, a^{40} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 1512 \, a^{40} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 8127 \, a^{40} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{a^{45}}}{1008 \, d} \]
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Time = 14.78 (sec) , antiderivative size = 149, normalized size of antiderivative = 0.89 \[ \int \frac {\sec ^2(c+d x)}{(a+a \cos (c+d x))^5} \, dx=\frac {3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{2\,a^5\,d}+\frac {3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{8\,a^5\,d}+\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7}{14\,a^5\,d}+\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9}{144\,a^5\,d}-\frac {10\,\mathrm {atanh}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{a^5\,d}-\frac {2\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{d\,\left (a^5\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2-a^5\right )}+\frac {129\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{16\,a^5\,d} \]
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